<?xml version="1.0" ?> 
<!--

For Flightgear 1.0 or later. Do not use for 1.9 or later.

  File:     WrightCyclone-975C18CB1.xml
  Author:   Aero-Matic v 0.7
  Date:     26 June 2005
  Version:  1.0

  Inputs:
    name:           WrightCyclone-975C18CB1
    type:           piston
    power:          2800 hp
    augmented?      no
    injected?       no


  References :
  ==========
  - http://www.hars.com.au/fleet/constellation/facts.html :
  (VH-EAG : 1049-F, C-121C).

  445 l/h per engine : 24790 l, 3450 NM, 16.5 h maximum.

  - http://www.superconstellation.org/ :
  (N73544 : 1049F, C-121C).

  450 l/h (120 US gal/h) per engine : 6550 US gal, 3500 NM, 14 h without reserve.

  Note that 1 US gal = 3.75 l.

  - http://www.airliners.net/discussions/general_aviation/read.main/1738757/4/ :

  Max payload : 1049 1890 NM, 1049C 2510 NM.
  Max fuel : 1049C : 4760 NM.

  - http://www.airweb.faa.gov/Regulatory_and_Guidance_Library/rgMakeModel.nsf/MainFrame?OpenFrameSet
  (FAA certificate, 6a5 - 14 may 1952) :

   Tanks 2 and 3 (inboard) : 790 gal each, 9480 lb.
         1 and 4 (middle) : 1555 gal each, 18660 lb.
         2a and 3a (outboard) : 565 gal each, 6780 lb.
         5 (center section) : 730 gal, 4380 lb.

   A total of 6550 US gal = 24563 l : note that is 1 US gal = 6 lb !
   This content is the same from model 1049-54 to 1049D-55 : from 1049G-82, there are additional tanks at wing tip. 

   - http://www.airweb.faa.gov/Regulatory_and_Guidance_Library/rgMakeModel.nsf/MainFrame?OpenFrameSet
   (FAA certificate, E-270 - 28 december 1983) :

   Displacement : 3350 cu. in.


--> 
<piston_engine name="Wright Cyclone 975C18CB1">

<!-- fakes displacement (3350) to increase the consumption and match the range :

     - one cannot change the volumetric efficiency.

     - estimation of the 1049 range : 3580 NM = 4760 * 1890 / 2510.
     Which matches VH-EAG and N73544 with both the same content in US gal.

     - max speed is 220 kt at 20000 ft (cruise), 197 kt at 25000 ft (ceiling) : that is an average of 209 kt.
     Let's take 319 kt as average ground speed (tail wind 20 kt) : range is 3580 NM / 319 kt = 11 hours.

     For our model 1049-54, with 6550 US gallons, the consumption must be 6550 / 11 hours = 595 US gallons / hour,
     or 149 US gallons / hour per engine.

     For westerly front wind 10 kt (optimistic), average ground speed is 289 kt (optimistic), or 3580 / 289 = 12 h.
     And it can cross the Atlantic from the east (KJFK-EHAM 3156 NM direct), only with refueling at Gander or Shannon.
-->

   <minmp unit="INHG">  6.0 </minmp>
   <maxmp unit="INHG"> 54.5 </maxmp>                                         <!-- aeromatic 30.0 -->
   <displacement unit="IN3"> 16000.00 </displacement>                        <!-- aeromatic 4480.00 -->
   <maxhp>    2800.00 </maxhp>
   <cycles>      2.0 </cycles>
   <idlerpm>   700.0 </idlerpm>
   <maxthrottle> 1.0 </maxthrottle>
   <minthrottle> 0.2 </minthrottle>

</piston_engine> 
